Respuesta :
Answer:
ns^2 np^5
Explanation:
Now let us try to analyse our options carefully in order to make an informed decision about the correct answer.
The answer cannot be ns^2 since any atom with this configuration must be a metal in group 2. Secondly, ns^2 np^2 is an element in group 14. Again, this specie cannot have the most negative electron affinity. The atom whose outermost electron configuration is ns^2 np^6 must be a noble gas since the outermost shell possesses eight electrons. This cannot be the answer we are seeking for.
However, an outermost electron configuration of ns^2 np^5 will apply to a halogen. Halogens have a very negative electron affinity. Hence a specie with this electron configuration must have the most negative electron affinity among the options.
The correct answer to the question is Option C. ns² np⁵
Let n represent the valence shell.
NOTE: Valence shell is the outermost shell of an atom.
Thus, we shall determine the valence electrons for each options given in the question.
For Option A
Valence shell = ns²
Valence electron = 2
For Option B
Valence shell = ns²np²
Valence electron = 2 + 2
Valence electron = 4
For Option C
Valence shell = ns²np⁵
Valence electron = 2 + 5
Valence electron = 7
For Option D
Valence shell = ns²np⁶
Valence electron = 2 + 6
Valence electron = 8
- Electronegativity is the tendency of an atom to attract electron(s). Atoms with more valence electrons tends to attract electrons more.
- From the illustraton above, we can see that Option C has 7 valence electrons while Option D has 8 valence
- Option D shows that the atom has completely filled outermost shell and as such, it does not attract electron(s)
- Option C has the highest valence electron (i.e 7) besides option D which do not attract electrons. Therefore, atom with 7 valence electrons will have a higher electronegativity.
Therefore, Option C. ns² np⁵ gives the correct answer to the question.
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