Hi can someone please help me.

The bases of a right triangle measure x-3 and x+4. If the hypotenuse of the triangle is 2x-3, what is the length of the hypotenuse?

Respuesta :

Answer:

13 units.

Step-by-step explanation:

By Pythagoras:

(x -3)^2  + (x + 4)^2 = (2x - 3)^2

x^2 - 6x + 9 + x^2 + 8x + 16 = 4x^2 -12x + 9

4x^2 - x^2 - x^2  + 6x - 8x - 12x + 9 - 9 - 16 = 0

2x^2 -14x - 16 = 0

2(x^2 - 7x - 8) = 0

2(x -8)(x + 1) =0

x = 8, -1.

As x must be positive we take x = 8

So the hypotenuse is  2(8) - 3 = 13 units long.