Answer:
The value of the test statistic is 4.26.
Step-by-step explanation:
In this case a hypothesis test is performed to determine whether most adults would erase all of their personal information online if they could.
A random sample of n = 453 adults were selected and it was found that 60% of them would erase all of their personal information online if they could.
Assume that the population proportion is, p = 0.50.
A z-test for single proportion would to used to perform the test.
Compute the value of the test statistic as follows:
[tex]z=\frac{\hat p-p}{\sqrt{\frac{p(1-p)}{n}}}[/tex]
[tex]=\frac{0.60-0.50}{\sqrt{\frac{0.50(1-0.50)}{453}}}\\\\=\frac{0.10}{0.0235}\\\\=4.25532\\\\\approx 4.26[/tex]
Thus, the value of the test statistic is 4.26.
