The power output of the solar cell = 627 watts
The efficiency of the solar cell = 4.6%
Given data :
Open circuit voltage ( Ocv ) = 0.60 V
Reverse saturation current density ( Io ) = 3.9 * 10⁻⁹ A/m²
Temperature of cell = 27°C
Cell voltage = 0.52 V
Cell area = 28m²
solar radiation = 485 w/m²
Step 1 : Determine the maximum power ( Pmax )
Pmax = [tex]\frac{e*v_{max}^{2} }{K*k+e*v_{max} } (I_{sc} + I_{0} )[/tex] ---- ( 1 )
where : e = 1.602 * 10⁻¹⁹ , Vmax = 0.52 v, Io = 3.9 * 10⁻⁹, Isc = 46.51 A/m² ( calculated value ), K = 1.381 * 10⁻²³ , k = 300
Input values into equation ( 1 ) above
Pmax = 22.39 A/m²
Step 2 : Determine the output power ( Pout )
Pinput = solar irradiation * cell area
= 485 * 28 = 13580 watts
Also
Pout = Pmax * cell area
= 22.39 * 28 = 627 watts ( power output )
Step 3 : determine the efficiency of the solar cell
efficiency of the solar cell = Pout / Pin
= 627 / 13580 = 0.046 = 4.6%
Hence we can conclude that The power output of the solar cell = 627 watts and The efficiency of the solar cell = 4.6%
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