A wood pole with a diameter of 10 in. has a moisture content of 5%. The fiber saturation point (FSP) for this wood is 30%. The wood shrinks or swells 1% (relative to the green dimensions) in the radial direction for every 5% change in moisture content below FSP. a. What would be the percent change in the wood's diameter if the wood's moisture is increased to 55%? b. Would the wood swell or shrink? c. What would be the new diameter?

note : moisture fluctuations from 5% to 30% causes dimensional changes in the wood but above 30% up to 55% causes no change. hence this formula can be used to calculate percentage change in the wood's diameter

Δd/d = 1/5(30 - 5)

Δd/d = 5%

Δd = 5%

B) would the wood swell or shrink

The wood would swell since the moisture content is increasing which will also led to increase in the wood's diameter

C) The new diameter of the wood

D2 = D + D( [tex]\frac{M1}{100}[/tex] )

D = initial diameter= 10 in , M1 = initial moisture content = 5%

therefore D2 = 10 + 10( 5/100 )

new diameter (D2) = 10.5 in

ogorwyne ogorwyne · Answer 2 · 2022-03-08T12:45:50+01:00

The change in the diameter of the wood would be 5%

the new diameter would be 10.5 inches

Wood pole diameter = 10 inches

Moisture content = 5%

Fiber saturation point = 30 %

The change in diameter would be

[tex]\frac{1}{5} (30-5)[/tex]

= 25/5

= 5%

The percentage change in the diameter of the wood would be 5%

b. This wood is going to rise up instead of shrinking. This is due to the fact that the moisture content that it has has gone up by 55%

c. The new diameter that this wood would have

diameter = 10

moisture = 5%

D = D+D(m)

= 10 + 10(5%)

= 10.5 inches

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