Answer:
[tex]6 \sqrt{61} \div 61[/tex]
is ans
Step-by-step explanation:
given, a=5 and b=6
as the refrence angle is thit
p=6 and b= 5
[tex]now \: h \: = \sqrt{p {}^{2} + b {}^{2} } [/tex]
[tex] = \sqrt{6 { }^{2} + 5 {}^{2} } [/tex]
[tex] \sqrt{61} = [/tex]
therefore h
[tex] = \sqrt{61} [/tex]
now cos thita =b/h
therefore cos thita=
[tex]6 \sqrt{61} \div 61[/tex]
...is ans..
