Answer:
(35k + 20) cents
Step-by-step explanation:
First of all, let us have the value of each unit:
1 quarter = 25 cents
1 nickel = 5 cents
1 dime = 10 cents
Given that number of quarter = k
Quarters are 5 lesser than Nickels, so number of nickels = k+5
One more than twice as many dimes as quarters:
k = 2 [tex]\times[/tex] Number of Dimes + 1
So, number of dimes = [tex]\frac{1}{2}(k-1)[/tex]
Value of quarters = [tex]25 \times k[/tex] cents
Value of nickels = [tex]5 \times (k+5) = (5k+25)\ cents[/tex]
Value of dimes = [tex]\frac{1}{2}(k-1) \times 10 = (5k-5)\ cents[/tex]
So, total value of coins =
[tex]25k + 5k +25 +5k-5\\\Rightarrow (35k+20)\ cents[/tex]
