Answer:
t = 3.79 s
Explanation:
We have,
A football is kicked at ground level with a speed of 18.6 m/s at an angle of 44.9 to the horizontal.
It means that,
Initial speed of a football, u = 18.6 m/s
Final speed of a football, v = 0 (when it hits the ground)
It would under the action of gravity. Let t is the time of motion. So, using equation of kinematics to find it.
v=u+at
a=-g
[tex]t=\dfrac{v-u}{a}\\\\t=\dfrac{0-18.6}{-9.8}\\\\t=1.89\ s[/tex]
The total time before the ball hits the ground is the sum of time taken to come down and time taken to go up. So, total time is 2×1.89 = 3.79 s
