Complete the following proof. Given: Points R, S, T, Q on circle O Prove: m \overarc R S + m \overarc S T + m \overarc T Q = m \overarc R Q

Answer:
Answer is below.
Step-by-step explanation:
Points R, S, T, Q on Circle O - Given
m (arc) RS + m (arc) ST = m (arc) RT , m (arc) RT + m (arc) TQ = m (arc) RQ - Arc addition
m (arc) RS + m (arc) ST + m (arc) TQ = m (arc) RQ - Substitution
Hope this helps.
The proofing is as follows:
Given that,
Now
m (arc) RS + m (arc) ST = m (arc) RT , m (arc) RT + m (arc) TQ = m (arc) RQ - Arc addition
And,
m (arc) RS + m (arc) ST + m (arc) TQ = m (arc) RQ - Substitution
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