Respuesta :
Answer:
1. CYNARG
Step-by-step explanation:
This a example of Caesar's Cipher, in which each letter in the original word leads to a ciphered letter according to the following equation:
[tex]C = (P + o) \text{mod} 26[/tex]
In which C is the index of the Ciphered letter in the alphabet, P is the index of the original letter and o is the offset.
Finding the offset:
O is coded B
O is the 15th letter in the alphabet, so [tex]P = 15[/tex].
B is the 2nd letter in the alphabet, so [tex]C = 2[/tex]
[tex]C = (P + o) \text{mod} 26[/tex]
[tex]2 = (15 + o) \text{mod} 26[/tex]
[tex]|o = |2-15| \text{mod} 26[/tex]
[tex]o = 13[/tex]
So
[tex]C = (P + 13) \text{mod} 26[/tex]
PLANET:
P
P is the 16th letter in the alphabet.
[tex]C = (16 + 13) \text{mod} 26 = 3[/tex]
So P is coded C.
L
L is the 12th letter in the alphabet:
[tex]C = (12 + 13) \text{mod} 26 = 25[/tex]
L is coded Y(25th letter in the alphabet)
A
A is the 1st letter in the alphabet
[tex]C = (1 + 13) \text{mod} 26 = 14[/tex]
A is coded N
N
N is the 14th letter in the alphabet
[tex]C = (14 + 13) \text{mod} 26 = 1[/tex]
N is coded A
E
E is the 5th letter in the alphabet
[tex]C = (5 + 13) \text{mod} 26 = 18[/tex]
E is coded R
So the correct answer is:
1. CYNARG
