the probability of rolling a 6 on a biased dice is 1/5 1) complete the tree diagram. 2) Work out the probability of rolling two sixes.

Answer:
Step-by-step explanation:
Not 6 on all rolls in the diagram = 4/5
6 on all rolls in the diagram is 1/5
To find the probablity of rolling two sixes, 1/5 x 1/5 = 4/100 = 0.04 = 4%
1) The completed tree diagram is attached
2) The probability of rolling two sixes as worked out from the tree diagram is; P(6 | 6) = ¹/₂₅
Since the probability of rolling a six on the first roll is 1/5, then probability of not rolling a six on first roll is;
P(not 6) = 1 - 1/5
P(not 6) = 4/5
A) Please find attached the completed tree diagram
B) First Roll;
P(6) = ¹/₅
P(not 6) = ⁴/₅
Second Roll;
Let's begin with the P(6) Section;
P(6 | 6) = ¹/₅ × ¹/₅ = ¹/₂₅
P(6 | not 6) = ¹/₅ × ⁴/₅ = ⁴/₂₅
Let us now solve for the P(not 6) section;
P(not 6 | 6) = ⁴/₅ × ¹/₅ = ⁴/₂₅
P(not 6 | not 6) = ⁴/₅ × ⁴/₅ = ¹⁶/₂₅
Now, since we are looking for the probability of getting two sixes, it is gotten from the above; P(6 | 6) = ¹/₅ × ¹/₅ = ¹/₂₅
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