Pls help with the solution of the question.

Answer:
[tex]\frac{17}{13}[/tex]
Step-by-step explanation:
Given
tan x = [tex]\frac{5}{12}[/tex] = [tex]\frac{opposite}{adjacent}[/tex]
5 and 12 are the legs of a 5- 12- 13 right triangle with hypotenuse 13, thus
sin x = [tex]\frac{opposite}{hypotenuse}[/tex] = [tex]\frac{5}{13}[/tex]
cos x = [tex]\frac{adjacent}{hypotenuse}[/tex] = [tex]\frac{12}{13}[/tex]
Thus
sin x + cos x = [tex]\frac{5}{13}[/tex] + [tex]\frac{12}{13}[/tex] = [tex]\frac{17}{13}[/tex]