Answer:
The bat and the ball were in contact for 1.8 x 10⁻³ s
Explanation:
Given;
mass of baseball, m = 0.14 kg
initial velocity of the baseball, u = 27.1 m/s
applied force in opposite direction, F = -5000 N
final velocity in opposite direction, v = -37 m/s
Note: The applied force and final velocity are negative because they act in opposite direction to the initial velocity.
impulse received by the body = change in momentum of the body
Ft = Δmv
Ft = mv - mu
Ft = m(v-u)
t = m(v-u) / F
[tex]t = \frac{0.14(-37-27.1)}{-5000} \\\\t = \frac{0.14(-64.1)}{-5000} \\\\t = \frac{-8.974}{-5000} \\\\t = 0.0018 \ s\\\\t = 1.8*10^{-3} \ s[/tex]
Therefore, the bat and the ball were in contact for 1.8 x 10⁻³ s
