Answer:
Step-by-step explanation:
[tex]A(-3,-2) and B(1,6).\\\\x_1 = -3\\y_1 = -2\\x_2 = 1\\y_2 =6\\\frac{y-y_1}{x-x_1} =\frac{y_2-y_1}{x_2-x_1} \\\frac{y -(-2)}{x -(-3)} =\frac{6-(-2)}{1-(-3)}\\\frac{y+2}{x+3} = \frac{6+2}{1+3} \\\frac{y+2}{x+3} = \frac{8}{4} \\Cross-multiply\\4(y+2) =8(x+3)\\4y +8 =8x+24\\4y = 8x +24-8\\4y = 8x+16 \\OR\\ y = 2x+4[/tex]