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You intend to estimate a population mean with a confidence interval. You believe the population to have a normal distribution. Your sample size is 4. Find the critical value that corresponds to a confidence level of 98%. (Report answer accurate to three decimal places with appropriate rounding.)

Respuesta :

Answer:

T = 4.541

Step-by-step explanation:

We don't have the standard deviation for the population, so we use the t-distribution.

The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So

df = 4 - 1 = 3

98% confidence interval

Now, we have to find a value of T, which is found looking at the t table, with 3 degrees of freedom(y-axis) and a confidence level of [tex]1 - \frac{1 - 0.98}{2} = 0.99[/tex]. So we have T = 4.541

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