Answer:
P = 0.00072
Step-by-step explanation:
If the number of traffic accidents that occurs follows a Poisson distribution, the probability that x traffic accidents occurs is:
[tex]P(x)=\frac{e^{-m}(m^x)}{x!}[/tex]
Where m is the mean. So replacing m by 8.1 accidents/monts, we get:
[tex]P(x)=\frac{e^{-8.1}(8.1^x)}{x!}[/tex]
So, the probability that the next two months will both result in three accidents each occurring in this stretch of road is calculated as:
[tex]P(3)*P(3)=\frac{e^{-8.1}(8.1^3)}{3!}*\frac{e^{-8.1}(8.1^3)}{3!}\\P(3)*P(3)=0.00072[/tex]
