Two cannonballs are dropped from a second-floor physics lab at height h above the ground. Ball B has four times the mass of ball A. When the balls pass the bottom of a first-floor window at height above the ground, the relation between their kinetic energies, KA and KB, is

If the mass is multiplied by 4, then, the kinetic energy must be increased by 4 as well. Since they will be travelling at the same speed when they are at the same point, the relation between KA and KB must be 1:4 or 1/4. Hope this helps!

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pristina pristina · Answer 2 · 2022-02-25T14:05:28+01:00

The relation between the kinetic energies of the freely falling balls A and B is obtained as [tex]\frac{KE_{A}}{KE_{B}} =\frac{1}{4}[/tex].

Kinetic Energy

The kinetic energy of an object depends on the mass and velocity with which it moves.

While under free-fall, the mass of an object does not affect the velocity with which it falls.

So, the velocities of both the balls are the same.

Let the mass of ball A is 'm'

So, the mass of ball B is '4m'

The kinetic energy of ball A is given by;

[tex]KE_{A}=\frac{1}{2} mv^2[/tex]

The kinetic energy of ball B is given by;

[tex]KE_{B}=\frac{1}{2} 4mv^2 = 2mv^2[/tex]

Therefore, the ratio of kinetic energies of A and B is,

[tex]\frac{KE_{A}}{KE_{B}} =\frac{1}{4}[/tex]

Learn more about kinetic energy here:

https://brainly.com/question/11580018