Tom and Jerry are selling fruit for a charity fundraiser. Customers can buy small boxes of oranges and large boxes of oranges. Tom sold 3 small boxes of oranges and 14 large boxes of oranges for a total of $203. Jerry sold 11 small boxes of oranges and 11 large boxes of oranges for a total of $220. Find the cost each of one small box of oranges and one large box of oranges. Please use equations to solve the problem.

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Step-by-step explanation:

3x + 14y = 203

2. 11x + 11y = 220

3. Divide the last equation above by 11: x + y = 20

4. This is the same as saying x = 20 - y

5. Now, substitute for x in the first equation: 3(20 - y) + 14y = 203

6. The above equation simplifies to 60 - 3y + 14y = 203

7. Now express the equation in terms of y: 11y = 143

8. From the last equation, y = 13

9. Since x + y = 20, x = 7

10. Check: (3 times 7) + (14 times 13) = 21 + 182 = 203;

(11 times 7) + (11 times 13) = 77 + 143 = 220

One small box of oranges costs is $[tex]7[/tex].

One Large box of oranges costs is $[tex]13[/tex].

Cost Price:

Cost price is the total amount of money that it costs a manufacturer to produce a given product or provide a given service. A cost price includes all outlays that are required for production, including property costs, materials, power, research and development, testing, worker wages, and anything else that must be paid for.

Tom sold 3 small boxes and 14 large boxes of orange for a total of $[tex]203[/tex]

[tex]\Rightarrow 3S+14L=203......(1)[/tex]

Jerry sold [tex]11[/tex] small boxes and [tex]11[/tex] large boxes of oranges for a total of $[tex]220[/tex]

[tex]\Rightarrow 11S+11L=220.....\left ( 2 \right )[/tex]

Solving equations (1) and (2), we get;

[tex]L=\frac{1573}{121}=13 \\ L=13[/tex]

Substitute [tex]L=13[/tex] in equation (2)

[tex]\Rightarrow 11S+11(13)=220[/tex]

[tex]S=\frac{77}{11}=7[/tex]

[tex]\therefore[/tex] One small box of oranges costs is $[tex]7[/tex].

One Large box of oranges costs is $[tex]13[/tex].

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