Answer:
[tex]\alpha=1-0.96 =0.04[/tex]
And [tex]\alpha/2= 0.02[/tex] and if we use the following function on the Ti84 plus we got:
invNorm(0.02,0,1)
invNorm(1-0.02,0,1)
And the values with the middle 96% of the values are:
[tex]z_{\alpha/2}= \pm 2.054[/tex]
Step-by-step explanation:
For this case we want to find the limits with the middle 96% of the area below the normal curve, then the significance level would be:
[tex]\alpha=1-0.96 =0.04[/tex]
And [tex]\alpha/2= 0.02[/tex] and if we use the following function on the Ti84 plus we got:
invNorm(0.02,0,1)
invNorm(1-0.02,0,1)
And the values with the middle 96% of the values are:
[tex]z_{\alpha/2}= \pm 2.054[/tex]