Answer:
First graph
Step-by-step explanation:
Here we have x ≥ 0, and y ≥ - 2, not x ≥ 0 and y ≥ 0. Thus, it doesn't restricts us fully to quadrant 1, but somewhat off considering y ≥ - 2. Now all we have to do is plot the following system of inequalities -
[tex]\begin{bmatrix}8x+12y\le \:92\\ 11x+7y\le \:79\\ x+y\ge \:5\end{bmatrix}[/tex]
Convert each into slope intercept form -
[tex]\begin{bmatrix}y\le \frac{23-2x}{3}\\ y\le \frac{79-11x}{7}\\ y\ge \:5-x\end{bmatrix}[/tex]
Which should be bounded by a small region similar to graph 1! The shaded region represents each intersection with respect to their restriction to quadrant 1.
Hope that helps!
