Answer:
93°
Step-by-step explanation:
[tex]\dfrac{|AC|}{\sin B}=\dfrac{|AB|}{\sin C}\\\\\dfrac{9}{\sin38^o}=\dfrac{11}{\sin C}\\\\\dfrac{\sin38^o}9=\dfrac{\sin C}{11}\\\\\sin C=\frac{11}9\sin38^o =\frac{11}9\cdot0,6157=0,7525(2)\\\\\sin C\approx0,7525\quad\iff\quad |\angle C|\approx48^o48'\\\\|\angle A|=180^o-|\angle B|-|\angle C|\\\\|\angle A|=180^o-38^o-48^o48'\\\\|\angle A|=93^o12'\approx93^o[/tex]
