Answer:
3/3.61 = 6/7.22 (C)
A complete question related to this found on chegg is stated below:
Triangle BAC was dilated from triangle BDE at a scale factor of 2. What proportion proves that sin∠D = sin∠A? A 2/3.61 = 4/7.22
B 3/2 = 6/4
C 3/3.61 = 6/7.23
D 2/3 = 4/6
Find attached the diagram.
Step-by-step explanation:
∆ BAC and ∆BDE are similar right angled triangles.
This is because when a shape is dilated, the new shape would be similar to the original shape but with different size. Each if the angles in both shapes remain the same.
Scale factor = 2
BE = 3, BD = 2, DE = 3.61
Each of the corresponding sides of ∆BDE will be multiplied to get each of the corresponding sides of ∆ABC.
BC = 2×BE = 2×3 = 6
AB = 2×DE = 2×3.61 = 7.22
See second diagram
sin∠D = opposite/hypotenuse = BE/DE
BE/DE = 3/3.61
sin∠A = BC/AC
BC/AC = 6/7.22
Therefore sin∠D = sin∠A:
3/3.61 = 6/7.22 (C)
