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At the lowest point in a vertical dive (radius = 0.58 km), an airplane has a speed of 300 km/h which is not changing. Determine the magnitude of the acceleration of the pilot at this lowest point. Group of answer choices

Respuesta :

Answer:

The centripetal acceleration is [tex]a = 11.97 \ m/s^2[/tex]

Explanation:

From the question we are told that

     The radius  is [tex]r = 0.58 \ km = 0.58 * 1000 = 580 \ m[/tex]

      The speed is [tex]v = 300\ km /hr = \frac{300 *1000}{1 * 3600 } = 83.33 \ m/s[/tex]

The centripetal acceleration of the pilot is mathematically represented as

       [tex]a = \frac{v^2 }{r}[/tex]

substituting  values

      [tex]a = \frac{(83.33)^2 }{580}[/tex]

     [tex]a = 11.97 \ m/s^2[/tex]