Answer:
B 6.15g.
Explanation:
As per the chemical equation, the reaction ratio between O2 and CO^2 is 2:1, which indicates there is 1 mole of CO^2 produced for every 2 moles of O2 responded.
Now we have to apply the molar mass and mass of O^2 to determine the moles of O^2 i.e
As we know that
[tex]moles\ of\ O^2 = \frac{mass\ of\ O^2}{molar\ mass\ of\ O^2}[/tex]
[tex]= \frac{8.94g}{32.00g/mol}[/tex]
= 0.2794 mole.
So, the moles of CO2 that produced is
[tex]= \frac{0.2794\ moles}{2}[/tex]
= 0.1397 mole
Now we have to apply the moles and molar mass CO^2 to find out the mass of CO^2 which is shown below:
As we know that
[tex]Mass\ of\ CO^2 = moles\ of\ CO^2 \times molar\ mass\ of\ CO^2[/tex]
[tex]= 0.1397 mole \times .44.01g/mole[/tex]
= 6.15 g
