The new size of the picture is [tex]4\times 8[/tex]and the new size of the mat is [tex]6\times8[/tex]This is shown in attached images.
Given-
The size of the photograph is 2 by 4 in.
- Marissa's photograph original size is 2 by 4 in. This is shown in the graph with image one.
- The boundary required for the mat is 1 in after the photograph applied. Thus the length of the mat must be 3 by 5 in. Refer Image two.
- When Marissa decided to the picture by the scale factor two she need to multiply its dimension with two.
Thus the new dimension of the Picture is,
[tex]=2\times(2,4)[/tex]
[tex]=(4,8)[/tex]
- Hence the new size for the picture is 4 by 8 in. This is shown in graph in image three.
- When Marissa decided to dilate the mat by the scale factor two she need to multiply its dimension with two.
Thus the new dimension of the mat is,
[tex]=2\times(3,5)[/tex]
[tex]=(6,10)[/tex]
- Hence the new size for the mat is 6 by 10 in. This is shown in graph in image four.
Hence the new size of the picture is 4 by 8 and the new size of the mat is 6 by 10. This is shown in attached images.
For more about the scaling the graph follow the link below-
https://brainly.com/question/13819784
