Respuesta :
Answer:
The distance from the pivot point that the small child will sit in order to maintain the balance is 1.8 m
Explanation:
Given;
mass of the bigger child, M = 30 kg
mass of the smaller child, m = 20 kg
distance between the two children, d = 3 m
This information can be represented diagrammatically;
3m
|<------------------------------------------------>|
----------------------------------------------------------------------------
↓ x Δ 3-x ↓
20kg 30kg
x is the distance from the pivot point that the small child will sit in order to maintain the balance
Take moment about the pivot;
Clockwise moment = anticlockwise moment
30(3-x) = 20x
90 -30x = 20x
90 = 20x + 30x
90 = 50x
x = 90 / 50
x = 1.8 m
Therefore, the distance from the pivot point that the small child will sit in order to maintain the balance is 1.8 m
The distance from the pivot point which the small child must sit in order to maintain the balance is 1.8 meters.
- Let the first child be A.
- Let the second child be B.
Given the following data:
- Mass of A = 20.0 kg
- Mass of B = 30.0 kg
- Distance = 3.00 m
To determine what distance from the pivot point is the small child sitting in order to maintain the balance, we would take moment about a pivot:
- Let the distance from the pivot be n.
Note: The distance of the child from the pivot is equal to [tex]3-n[/tex]
For moment:
Clockwise moment = anticlockwise moment
[tex]30(3-n) = 20n\\\\90-30n=20n\\\\90=20+30n\\\\90=50n\\\\n=\frac{90}{50}[/tex]
n = 1.8 meters
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