Answer:
Her temperature is 97.27ºF.
Step-by-step explanation:
Z-score:
In a set with mean [tex]\mu[/tex] and standard deviation [tex]\sigma[/tex], the zscore of a measure X is given by:
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question:
[tex]\mu = 98.2, \sigma = 0.62[/tex]
Z = -1.5. What is her temperature?
Her temperature is X when Z = -1.5. So
[tex]Z = \frac{X - \mu}{\sigma}[/tex]
[tex]-1.5 = \frac{X - 98.2}{0.62}[/tex]
[tex]X - 98.2 = -1.5*0.62[/tex]
[tex]X = 97.27[/tex]
Her temperature is 97.27ºF.
