what is the molarity of a solution that contains 49.8 grams of nai and is dissolved in enough water to make 1.50 liters

Respuesta :

Answer: The molarity of solution is 0.221 M

Explanation:

Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

[tex]Molarity=\frac{n}{V_s}[/tex]

where,

n = moles of solute

[tex]V_s[/tex] = volume of solution in L

moles of [tex]NaI[/tex] = [tex]\frac{\text {given mass}}{\text {Molar mass}}=\frac{49.8g}{149.89g/mol}=0.332mol[/tex]

Now put all the given values in the formula of molality, we get

[tex]Molarity=\frac{0.332mol}{1.50L}[/tex]

[tex]Molarity=0.221mol/L[/tex]

Therefore, the molarity of solution is 0.221 M