4.15 Calculate the composition, in weight percent, of an alloy that contains 218.0 kg titanium, 14.6 kg of aluminum, and 9.7 kg of vanadium.

Respuesta :

Answer:

The composition of the allow, in weigh percent, is 89.971 % Titanium, 6.026 % Aluminium and 4.003 % Vanadium.

Explanation:

The weight percentage of a element in an allow is equal to the mass of the element divided by the total mass of the allow and multiplied by 100. Then:

Titanium (Ti)

[tex]\% m_{Ti} = \frac{m_{Ti}}{m_{Ti}+m_{Al}+m_{V}}\times 100\,\%[/tex]

[tex]\%m_{Ti} = \frac{218\,kg}{218\,kg+14.6\,kg+9.7\,kg}\times 100\,\%[/tex]

[tex]\%m_{Ti} = 89.971\,\%[/tex]

Aluminium (Al)

[tex]\% m_{Al} = \frac{m_{Al}}{m_{Ti}+m_{Al}+m_{V}}\times 100\,\%[/tex]

[tex]\%m_{Al} = \frac{14.6\,kg}{218\,kg+14.6\,kg+9.7\,kg}\times 100\,\%[/tex]

[tex]\%m_{Al} = 6.026\,\%[/tex]

Vanadium (V)

[tex]\% m_{V} = \frac{m_{V}}{m_{Ti}+m_{Al}+m_{V}}\times 100\,\%[/tex]

[tex]\%m_{V} = \frac{9.7\,kg}{218\,kg+14.6\,kg+9.7\,kg}\times 100\,\%[/tex]

[tex]\%m_{Al} = 4.003\,\%[/tex]

The composition of the allow, in weigh percent, is 89.971 % Titanium, 6.026 % Aluminium and 4.003 % Vanadium.