Answer:
[tex] log(216 ) = log(2 ^{3} \times 3 ^{3} ) \\ log(216) = a ^{3} \times b ^{3} [/tex]
The value of the log(216) when log 2=a,and log 3=b is 2.3344.
We have given that,
log 2=a, log 3=b
logarithm, the exponent or power to which a base must be raised to yield a given number.
[tex]log(216)=\log _{10}\left(6^3\right)[/tex]
[tex]log(216)=\log _{10}\left(2\times 3)^3\right)\\log(216)=\log _{10}(2^3\times 3^3)\\log(216) =3\log _{10}\left(6\right)[/tex]
Therefore the value of the log(216)=3log(6).
That is log(216)=2.3344.
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