Answer:
solution,
[tex]4 {x}^{2} + 5x - 6 \\ = 4 {x}^{2} + (8 - 3)x - 6 \\ = 4 {x}^{2} + 8x - 3x - 6 \\ = 4x(x + 2) - 3(x + 2) \\ = (x + 2)(4x - 3)[/tex]
Hope this helps...
Good luck on your assignment.
4(x-1)(x+6)
Step-by-step explanation:
-1 x 6 = -6
-1+6=5
Put 4 out of the way while factoring
Then add it back once you've found your two numbers
The roots (zeros) are 1 and -6
Hope this helps!
