Based on the bond energies for the reaction below, what is the enthalpy of the reaction? HC≡CH (g) + 5/2 O₂ (g) → 2 CO₂ (g) + H₂O (g) Any help would be greatly appreciated!

Based on the bond energies, the reaction HC≡CH(g) + 5/2 O₂(g) → 2 CO₂(g) + H₂O(g) has a standard enthalpy of reaction of -1222 kJ/mol.

Let's consider the following reaction.

HC≡CH(g) + 5/2 O₂(g) → 2 CO₂(g) + H₂O(g)

Given the bond energies (E), we can calculate the standard enthalpy of the reaction (ΔH°rxn) using the following expression.

[tex]\Delta H\° _{rxn} = E(broken\ bonds) - E(formed\ bonds)[/tex]

The broken bonds are:

HC≡CH

1 triple C-C bond
2 single C-H bonds

O₂

5/2 double O-O bonds

The formed bonds are:

CO₂

4 double C-O bonds

H₂O

2 single O-H bonds

[tex]\Delta H\°_{rxn} = E(C\equiv C) + 2 E(C-H) + 5/2 E(O=O) - 4 E(C=O) - 2 E(O-H)\\\\\Delta H\°_{rxn} = 835kJ/mol + 2 (411kJ/mol) + 5/2 (494kJ/mol) - 4 (799kJ/mol) - 2 (459kJ/mol) = -1222 kJ/mol[/tex]

Based on the bond energies, the reaction HC≡CH(g) + 5/2 O₂(g) → 2 CO₂(g) + H₂O(g) has a standard enthalpy of reaction of -1222 kJ/mol.

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Based on the bond energies for the reaction below, what is the enthalpy of the reaction? HC≡CH (g) + 5/2 O₂ (g) → 2 CO₂ (g) + H₂O (g) **Any help would be greatly appreciated!**

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Based on the bond energies for the reaction below, what is the enthalpy of the reaction? HC≡CH (g) + 5/2 O₂ (g) → 2 CO₂ (g) + H₂O (g) Any help would be greatly appreciated!