Answer:
1/11
Step-by-step explanation:
even #s between (or including) 1 and 12:
2, 4, 6, 8, 10, 12
there are 6
6/12 for the first one
5/11 for the second one (one even # less)
4/10 for the third one
To find the probability of picking three even numbers from 1 to 12 in a row three times:
multiply the probabilities together:
(6/12)*(5/11)*(4/10)=(24/120)*(5/11)=(12/60)*(5/11)=(1/5)*(5/11)=5/55=1/11
