Answer:
2.9
Step-by-step explanation:
[tex]\left|\begin{array}{c|cc}$Number of TVs per Household&$Frequency\\----------&--\\0&1\\1&10\\2&24\\3&21\\4&16\\5&9\\6&1\\----------&--\\Total&82\end{array}\right|[/tex]
We want to find the mean number of TVs owned by these households.
Mean, [tex]\mu =\dfrac{\sum fx}{\sum f}[/tex]
[tex]\left|\begin{array}{c|c|c}$Number of TVs per Household(x)&$Frequency(f)&fx\\----------&--&----\\0&1&1\\1&10&10\\2&24&48\\3&21&63\\4&16&64\\5&9&45\\6&1&6\\----------&--&---\\&\sum f= 82&\sum fx =237\end{array}\right|[/tex]
Therefore, the mean number of TVs owned by these households is:
[tex]\mu =\dfrac{237}{82}=2.9 $ (correct to 1 d.p.)[/tex]