Answer:
[tex]\frac{5}{2} ; -4[/tex]
Step-by-step explanation:
2x² + 3x - 20 = 0
a = 2 ; b = 3 ; c = -20
[ -b ± √(b² - 4ac) ] /2a = [-3±√(3²-4*2*-20]/2*2
= [-3±√(9+160)]/4
= [-3±√169 ]/4
= [-3± 13]/4
= [tex]\frac{-3+13}{4} ;\frac{-3-13}{4}\\\\=\frac{10}{4} ; \frac{-16}{4}\\\\=\frac{5}{2} , -4[/tex]
2x² + 3x - 20 = 0
2x² + 8x - 5x - 20 = 0
2x(x+4) - 5(x+4) = 0
(x+4)(2x-5) = 0
x+4 = 0
x = -4
2x - 5 = 0
2x = 5
x = 5/2
