Answer:
[tex]z=\frac{180-150}{30}= 1[/tex]
And if we find the probability using the normal standard distribution we got:
[tex]P(z<1)=0.841[/tex]
And the the percentile would be approximately 84.1
Step-by-step explanation:
For this case we define the random variable of interest as "Score for girls" and we know the following parameters:
[tex]\mu =150, \sigma =30[/tex]
And we want to find the percentile for the score 180 and we can use the z score formula given by:
[tex] z=\frac{X -\mu}{\sigma}[/tex]
And replacing we got:
[tex]z=\frac{180-150}{30}= 1[/tex]
And if we find the probability using the normal standard distribution we got:
[tex]P(z<1)=0.841[/tex]
And the the percentile would be approximately 84.1
