Consider a normal population with the mean of 40 and standard deviation of 10. A random sample of was selected: 39.2, 45.7, 27.4, 25.9, 25.1, 46.3, 42.9, 49.0, 40.6, 47.0. What is the bias of this the estimated mean for this sample

Respuesta :

Answer:

[tex]\bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]

And replacing we got:

[tex]\bar X= 38.91[/tex]

And we can find the bias with this formula:

[tex] Bias= \bar X -\mu[/tex]

And replacing we got:

[tex] Bias = 38.91 -40 = -1.09[/tex]

Step-by-step explanation:

For this problem we know that the random variable of interest follows this distribution:

[tex]X \sim N(\mu =40, \sigma= 10)[/tex]

And we have the following random sample given:

39.2, 45.7, 27.4, 25.9, 25.1, 46.3, 42.9, 49.0, 40.6, 47.0

And we can calculate the sample mean with the following formula:

[tex]\bar X = \frac{\sum_{i=1}^n X_i}{n}[/tex]

And replacing we got:

[tex]\bar X= 38.91[/tex]

And we can find the bias with this formula:

[tex] Bias= \bar X -\mu[/tex]

And replacing we got:

[tex] Bias = 38.91 -40 = -1.09[/tex]