Answer:
[tex]3x+\frac{7}{6}y[/tex]
Step-by-step explanation:
To simplify the expression, we first open the parenthesis, then we collect all the like terms. Lastly we simplify the like terms to its simplest form. Given that:
[tex]\frac{1}{2}(3x-\frac{2}{3} y)+3(\frac{x}{2}+\frac{1}{2}y )\\\\Firstly, we\ expand\ the\ parenthesis:\\\\=\frac{1}{2}(3x)-\frac{1}{2}(\frac{2}{3} y)+3\frac{x}{2}+3(\frac{1}{2} y)\\[/tex]
[tex]=\frac{3}{2}x-\frac{1}{3}y +\frac{3}{2}x+\frac{3}{2} y\\\\ Collecting\ like\ terms:\\\\=\frac{3}{2}x+\frac{3}{2}x-\frac{1}{3}y+\frac{3}{2}y\\\\Adding \ terms:\\\\=3x +\frac{7}{6}y[/tex]
