Answer:
5.097 m
Explanation:
This involves Bernoulli's equation, so we will use;
P + ρgh + ½ρv² = constant
Applying this equation to both points, we have;
P_i + ρ_water*g*h_i + ½*ρ_water*v_i² = P_f + ρ_water*g*h_f + ½*ρ_water*v_f²
Since open to air, P_i and P_f will cancel out.
Also, v_i = 0 and h_f = 0
ρ_water = 1 g/ml
v_f is given as 10 m/s
h_i is depth of the hole below the water surface.
Thus, plugging in values, we have;
1*9.81*h_i + 0 = 0 + ½*1*10²
9.81h_i = 50
h_i = 50/9.81
h_i = 5.097 m
The water surface is 5.10 m below the hole.
Given data:
The diameter of circular hole is, d = 6.00 mm = 0.006 m.
The speed of water escaping through hole is, v = 10 m/s.
Here, we will apply the concept of kinematic equation of motion. As per the third kinematic equation of motion,
[tex]v^{2}=u^{2}+2gh[/tex]
here,
u is the initial speed of water.
g is the gravitational acceleration.
h is the vertical distance of hole from the water surface..
Solving as,
[tex]10^{2}=0^{2}+2(9.8)h\\\\100 = 19.6h\\\\h =5.10 \;\rm m[/tex]
Thus, we can conclude that the water surface is 5.10 m below the hole.
For more details, refer to the link:
https://brainly.com/question/21674779
