Answer:
180.1 g
Explanation:
Data provided in the question
Mass of lead sinker = 225 grams
Density = 11.3 g/cm^3
The Wooden block of mass = 25 grams
Density = 0.5/g cm^3
Based on the above information, the apparent weight is
Before that we need to do the following calculations
[tex]V_1 = \frac{m_1}{D_1}[/tex]
[tex]= \frac{225}{11.3}[/tex]
= 19.91 cm^3
[tex]V_2 = \frac{m_2}{D_2}[/tex]
[tex]= \frac{25}{0.5}[/tex]
= 50 cm^3
Now as we know that
V = V_1 + V_2
= 19.91 cm^3 + 50 cm^3
= 69.91 cm^3
Now the weight of dispacement of water is
[tex]m = VD_{water}[/tex]
[tex]= 69.91 cm^3 (1 \frac{g}{cm^3} )[/tex]
= 69.91 g
Therefore the apparent weight is
[tex]W = m_1 + m_2 - m[/tex]
= 225 + 25 - 69.91 g
= 180.1 g
