Answer
[tex]bc - 4b + 3c - 12[/tex]
solution,
[tex](b + 3)(c - 4) \\ = b(c - 4) + 3(c - 4) \\ = bc - 4b + 3c - 12[/tex]
hope it helps..
Answer:
[tex]bc - 4b + 3c - 12[/tex] apply de disruptive property by multiplying each term of b+3 by each term of c -4
