Answer:
Option c
Step-by-step explanation:
We are being asked to find unit vector u given the direction as x = < 40, 9 >. In most cases it would be v = < 40, 9 >, but it is the same concept.
To find the magnitude, given 40 and 9, you would do the following -
[tex]| v | = \sqrt{40^2 + 9^2},\\| v | = \sqrt{1600 + 81},\\\\| v | = 41[/tex]
We got the magnitude to be 41. Now let us find unit vector u through the following calculations -
[tex]u = < 40, 9 > / 41,\\u = < 40 / 41, 9 / 41 >[/tex]
And there you have it! The solution is option c!
