Answer:
The energy of exactly one photon of this light is 4.84*10⁻¹⁹ Joules
Explanation:
A photon is an elementary particle that, according to the principles of quantum physics, makes up light.
A photon is characterized by a wavelength, denoted by λ, or, by an energy, denoted by E.
The relationship between the amount of energy (E) transported by the photon, and its frequency (v), is determined by:
E= h*v
where, as mentioned, E is the energy v is the frequency and h is the Planck constant, whose value is 6,626 * 10⁻³⁴ Joules-sec.
In this case, the frecuency is 7.30*10¹⁴ Hz. Then:
E=6,626 * 10⁻³⁴ Joules-sec* 7.30*10¹⁴ Hz
Solving:
E= 4.84*10⁻¹⁹ Joules
The energy of exactly one photon of this light is 4.84*10⁻¹⁹ Joules
