Answer:
The arrow stay in flight for 26.92 seconds
Step-by-step explanation:
We are given that the height of an arrow shot from a bow on Mars is modeled by equation:
[tex]h(t) = 2.3 + 50t - 1.86t^2[/tex]
Where h(t) is the height of arrow
t is the time in seconds
Now we are supposed to find How long does the arrow stay in flight?
Substitute h(t)=0
So,[tex]2.3+50t-1.86t^2=0[/tex]
[tex]1.86t^2-50t-2.3=0[/tex]
t=-.04 , 26.92
Since the time cannot be negative
So,the arrow stay in flight for 26.92 seconds
