Respuesta :

Answer:

The answer is √74 = 8.6023

Magnitude of a line between two points can be written as

√( c - a)² + ( d - b)²

Where (a,b) and (c ,d) are two points

A(3,-1) and B(-2,6)

Magnitude of AB = √ ( -2 - 3)² + ( 6 + 1)²

= √ (-5)² + 7²

= √ 25 + 49

= √74 units = 8.6023 units

Hope this helps you.

We are being asked to determine the magnitude of a vector here, given the initial and terminal points. This would be in the form < v1, v2 >, so that you could state the following -

[tex]|| v || = v_{1}^2 + v_{2}^2[/tex]

Which could be rewritten as the following, in terms of the initial and terminal points -

[tex]|| v || =\sqrt{( P2 - P1^2 ) + ( Q1 - Q2)^2}[/tex]

Let's substitute known values and calculate || v || -

[tex]|| v || =\sqrt{( P2 - P1^2 ) + ( Q1 - Q2)^2},\\- 2 - 3, 6 - ( - 1 )\\< - 5, 7 >\\-------------------------\\|| v || = \sqrt{ ( - 5 )^2 + ( 7 )^2},\\|| v || = \sqrt{ 25 + 49},\\|| v || = \sqrt{74}[/tex]

Solution = Option B!