How many palindromes of length 5 can you form using letters with the following properties: they start with a consonant, and the consonants and vowels alternate; no letter appears more than twice. (Note: assume letters "a", "e", "i", "o", and "u" are the vowels of the English alphabet).

There are 21 consonants that can serve as the first and last letters. There are 5 vowels that can serve as the 2nd and 4th letters. There are 20 remaining consonants that can serve as the 3rd letter. (The same consonant cannot appear in all three places.)

So, the total number of 5-letter palindromes that start with a consonant and alternate with a vowel will be ...

21×5×20 = 2100 . . . different palindromes

sheenuvt12 sheenuvt12 · Answer 2 · 2022-07-21T06:58:35+02:00

2100 palindromes of length 5 can you form using letters.

What is palindrome?

A palindrome is a word, number, phrase, or other sequence of characters which reads the same backward as forward, such as madam or racecar.

As, there are 21 consonants that can be the first and last letter.

and, there 5 vowels that be the second and fourth letter .

lastly, the 20 remaining consonants that can be the 3rd letter.

So, the total number of 5-letter palindromes will be,

= 21×5×20

= 2100

Learn more about palindrome here:

https://brainly.com/question/19052372

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