what can you say about the y-values of the two functions f(x) =3x^2-3 and g(x)=2^x-3

Answer:
The answers are A and C. for A P E X.
Step-by-step explanation:
The option(A) minimum y-value of g(x) approches -3 and option(C) f(x) has the smallest possible y-value are correct.
It is defined as a special type of relationship and they have a predefined domain and range according to the function every value in the domain is related to exactly one value in the range.
We have a function:
[tex]\rm f(x) = 3x^2-3[/tex]
As we can see in the graph the first term is 3x² and is always positive for all x.
The range for f(x) ∈ [-3, ∞)
When x = 0
f(x) = -3
The above value is the smallest possible value on the y-axis.
For function:
[tex]\rm g(x) = 2^x-3[/tex]
[tex]\rm 2^x[/tex] is also a positive quantity and it is an exponential function.
The range for the g(x) ∈ (-3, ∞)
It means g(x) never toches the y-axis at -3.
We can say the minimum value of g(x) approaches -3
Thus, the option(A) minimum y-value of g(x) approches -3 and option(C) f(x) has the smallest possible y-value are correct.
Learn more about the function here:
brainly.com/question/5245372