Answer:
[tex]V(t) = 425(0.952)^{t}[/tex]
Step-by-step explanation:
The amount of water in the bucket after t hours, in mL, can be modeled by an equation in the following format:
[tex]V(t) = V(0)(1-r)^{t}[/tex]
In which V(0) is the initial amount, and r is the constant decay rate, as a decimal.
Bucket contains 425 mL of water.
This means that [tex]V(0) = 425[/tex]
The capacity of water in the bucket decreases 4.8% each hour.
This means that [tex]r = 0.048[/tex]
So
[tex]V(t) = V(0)(1-r)^{t}[/tex]
[tex]V(t) = 425(1-0.048)^{t}[/tex]
[tex]V(t) = 425(0.952)^{t}[/tex]
