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Find the area of the figure. If you need to use Pi in your computation, approximate its value as 3.14. Round to the nearest hundredth.
Rectangle topped by a semicircle

a.
45.12 sq. in.
b.
21.57 sq. in
c.
32.56 sq. in.
d.
26.28 sq. in.

Find the area of the figure If you need to use Pi in your computation approximate its value as 314 Round to the nearest hundredth Rectangle topped by a semicirc class=

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Answer:

area of figure= area of rectangle+area of semi-circle

area of rectangle= length ×width

5×4

= 20in²

area of semi circle= 1/2πr²

1/2×22/7×2×2

22×2

7

44

7

= 6.29in²

area of figure= 20+6.29

= 26.29in²

The area of the figure is the combined area of the rectangle and the two semicircles which are 26.29in².

What is the area of the rectangle?

The area of the rectangle is the product of the length and width of a given rectangle.

The area of the rectangle = length × Width

The area of figure= area of rectangle + area of the semi-circle

The area of rectangle = length ×width

                                     = 5 × 4

                                     = 20in²

The area of semi circle = 1/2πr²

                                       = 1/2×22/7×2×2

                                       = 6.29in²

The area of figure= area of rectangle + area of the semi-circle

= 20 + 6.29

= 26.29in²

Learn more about the area;

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