Answer:
a) Check the file attached below for the diagram
b) Change in velocity vector between F and G, [tex]\overrightarrow{\triangle V} = \overrightarrow{V_G}[/tex]
Explanation:
a) The diagram that represents the description is contained in the file attached to this solution. A vector, [tex]V_G[/tex] that represents the velocity of the object at point G is also indicated.
A very good point to note is that the direction of the velocity is always acting tangent to the path
b) The change in velocity vector between F and G
The change in velocity vector is [tex]\overrightarrow{\triangle V} = \overrightarrow{V_G} - \overrightarrow{V_F}[/tex]
Since the object starts from rest at point F, [tex]\overrightarrow{V_F} = 0[/tex]
Therefore, Change in velocity vector between F and G, [tex]\overrightarrow{\triangle V} = \overrightarrow{V_G}[/tex]